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05-17-2005
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Administrator
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Join Date: Apr 2004
Location: Lone Tree, CO
Posts: 16,777
Thanks: 11
Thanked 74 Times in 45 Posts
Rep Power: 10
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Happy Birthday AutumnThunder
With very littel fanfare (None at all), we had our 1st birthday on April 12, 2005.
First Ever Post is here (Not much to read, but this is your typical first post on any new forum).
The first post made by a member not including myself or Tom was by Sunday Slacker on April 22, 2004, when he muttered:
"What's this about my beloved G-men... Tom don't make me come out to Colorodo."
And with those words, the forums were officially open.
See Whole Thread here.
8,072 Posts later, things are picking up...Now, we average just about 2 new members per month, how about spreading the word and getting some new blood in here.
eoeleven has had 11 referrals. This is impressive. If everyone had 11 referrals, we would have over 300 Users here.
Anyway, Happy Birthday AutumnThunder!
__________________
--Kevin
AutumnThunder.com Administrator
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05-17-2005
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Off Cooridinator
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Join Date: Apr 2005
Location: BAITERVILLE
Age: 41
Posts: 3,141
Thanks: 0
Thanked 9 Times in 8 Posts
Rep Power: 28
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Who Is This Eo Character That You Keep Bringing Up?
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05-17-2005
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Team Owner
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Join Date: Jul 2004
Location: Texas
Posts: 21,738
Thanks: 102
Thanked 191 Times in 169 Posts
Rep Power: 68
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Man that is great HAPPY 1 year and growing every day!
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05-17-2005
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Administrator
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Join Date: Apr 2004
Location: Lone Tree, CO
Posts: 16,777
Thanks: 11
Thanked 74 Times in 45 Posts
Rep Power: 10
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Quote:
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Originally Posted by clarke
Actually, if everybody current had 11 referrals, and those people had 11 referrals, and those people had 11 referrals...and so forth, the number would be infitesimal (its referred to as the powers of two in some areas). So that last quote is limited in view.
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I thought the same thing, but I was not sure the people on this board would gasp the concept of the whole 11 people had 11 referrals and those 11 referrals had 11 referrals..etc.
So technically, we would have 1.74494023 × 10^31 people but that is assuming each new referral would have 11 additional referrals or:
r*cos(theta) + r*i*sin(theta))^n
= (r*(cos(theta) + i*sin(theta))^n
= (r^n) * (cos(theta) + i*sin(theta))^n
= (r^n) * (e^(i*theta))^n
= (r^n) * (e^(n*i*theta))
= (r^n) * (cos(n*theta) + i*sin(n*theta))
Of course, each person getting exactly 11 referrals is unlikely:
E(X) = (4)*(1/6) + (-1)*(5/6) = 4/6 - 5/6 = -1/6
Thus, the odds each person would get 11 additional referrals is: -(-1/6) = 1/6 or 16.67%.
...
__________________
--Kevin
AutumnThunder.com Administrator
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05-17-2005
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General Manager
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Join Date: Mar 2005
Location: Somewhere in Chiefs country
Posts: 9,153
Thanks: 25
Thanked 24 Times in 22 Posts
Rep Power: 40
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Quote:
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Originally Posted by administrator
I thought the same thing, but I was not sure the people on this board would gasp the concept of the whole 11 people had 11 referrals and those 11 referrals had 11 referrals..etc.
So technically, we would have 1.74494023 × 10^31 people but that is assuming each new referral would have 11 additional referrals or:
r*cos(theta) + r*i*sin(theta))^n
= (r*(cos(theta) + i*sin(theta))^n
= (r^n) * (cos(theta) + i*sin(theta))^n
= (r^n) * (e^(i*theta))^n
= (r^n) * (e^(n*i*theta))
= (r^n) * (cos(n*theta) + i*sin(n*theta))
Of course, each person getting exactly 11 referrals is unlikely:
E(X) = (4)*(1/6) + (-1)*(5/6) = 4/6 - 5/6 = -1/6
Thus, the odds each person would get 11 additional referrals is: -(-1/6) = 1/6 or 16.67%.
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 I hate math! and my referral is trying to get in...did you get Greg's e-mail?
__________________
The Colbert Report!
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05-17-2005
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Banned
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Join Date: Mar 2005
Location: TX
Age: 36
Posts: 6,875
Thanks: 0
Thanked 0 Times in 0 Posts
Rep Power: 0
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Quote:
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Originally Posted by administrator
I thought the same thing, but I was not sure the people on this board would gasp the concept of the whole 11 people had 11 referrals and those 11 referrals had 11 referrals..etc.
So technically, we would have 1.74494023 × 10^31 people but that is assuming each new referral would have 11 additional referrals or:
r*cos(theta) + r*i*sin(theta))^n
= (r*(cos(theta) + i*sin(theta))^n
= (r^n) * (cos(theta) + i*sin(theta))^n
= (r^n) * (e^(i*theta))^n
= (r^n) * (e^(n*i*theta))
= (r^n) * (cos(n*theta) + i*sin(n*theta))
Of course, each person getting exactly 11 referrals is unlikely:
E(X) = (4)*(1/6) + (-1)*(5/6) = 4/6 - 5/6 = -1/6
Thus, the odds each person would get 11 additional referrals is: -(-1/6) = 1/6 or 16.67%.
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You didn't know we all met in a 'differential equations' class?
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05-17-2005
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General Manager
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Join Date: Mar 2005
Location: Somewhere in Chiefs country
Posts: 9,153
Thanks: 25
Thanked 24 Times in 22 Posts
Rep Power: 40
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Quote:
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Originally Posted by administrator
With very littel fanfare (None at all), we had our 1st birthday on April 12, 2005.
First Ever Post is here (Not much to read, but this is your typical first post on any new forum).
The first post made by a member not including myself or Tom was by Sunday Slacker on April 22, 2004, when he muttered:
"What's this about my beloved G-men... Tom don't make me come out to Colorodo."
And with those words, the forums were officially open.
See Whole Thread here.
8,072 Posts later, things are picking up...Now, we average just about 2 new members per month, how about spreading the word and getting some new blood in here.
eoeleven has had 11 referrals. This is impressive. If everyone had 11 referrals, we would have over 300 Users here.
Anyway, Happy Birthday AutumnThunder!
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HAPPY BIRTHDAY AUTUMN THUNDER!!!
__________________
The Colbert Report!
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